vignettes/tutorial_raw_text.Rmd
tutorial_raw_text.Rmd
This tutorial gives an example of how to use akc
package
to carry out automatic knowledge classification based on raw text.
First, load the packages we need.
library(akc)
library(dplyr)
#>
#> Attaching package: 'dplyr'
#> The following objects are masked from 'package:stats':
#>
#> filter, lag
#> The following objects are masked from 'package:base':
#>
#> intersect, setdiff, setequal, union
In the dataset, we have the ID, title, keyword and abstract of documents. We are going to use the keyword as the dictionary to extract keywords from the abstract.
bibli_data_table
#> # A tibble: 1,448 × 4
#> id title keyword abstr…¹
#> <int> <chr> <chr> <chr>
#> 1 1 Keeping the doors open in an age of austerity? Qualita… Auster… "Engli…
#> 2 2 Comparison of Slovenian and Korean library laws Compar… "This …
#> 3 3 Analysis of the factors affecting volunteering, satisf… Contin… "This …
#> 4 4 Redefining Library and Information Science education a… Curric… "The p…
#> 5 5 Can in-house use data of print collections shed new li… Check-… "Libra…
#> 6 6 Practices of community representatives in exploiting i… Commun… "The p…
#> 7 7 Exploring Becoming, Doing, and Relating within the inf… Librar… "Profe…
#> 8 8 Predictors of burnout in public library employees Emotio… "Work …
#> 9 9 The Roma and documentary film: Considerations for coll… Academ… "This …
#> 10 10 Mediation effect of knowledge management on the relati… Job pe… "This …
#> # … with 1,438 more rows, and abbreviated variable name ¹abstract
keyword_clean
is designed to split the keywords and
removed pure numbers and contents in the parentheses. All letters would
be converted to lower case. Details see the help of
keyword_clean
, use “?keyword_clean”. After cleaning, we’ll
use these keywords to establish a dictionary.
Using keyword_extract
to extract keywords from the
abstract. Here, we also exclude the stop words using the “stopword”
parameter.
# get stop words from `tidytext` package
tidytext::stop_words %>%
pull(word) %>%
unique() -> my_stopword
bibli_data_table %>%
keyword_extract(id = "id",text = "abstract",
dict = my_dict,stopword = my_stopword) -> extracted_keywords
#> Joining, by = "keyword"
While this process has consider lots of factors, such as stemming, lemmatizing, etc. Here I’ll provide a easy implementation. For advanced usage, use “?keyword_merge” to find out.
extracted_keywords %>%
keyword_merge() -> merged_keywords
This process will construct a keyword co-occurrence network and use
community detection to group the keywords automatically. You can use
“top” or “min_freq” to control how many keywords should be included in
the network. “top” means how many keywords with largest frequency should
be included. “min_freq” means the included keywords should emerge at
least how many times. Default uses top = 200
and
min_freq = 1
.
merged_keywords %>%
keyword_group() -> grouped_keywords
Getting the result as a table could be easy by:
grouped_keywords %>%
as_tibble()
#> # A tibble: 203 × 3
#> name freq group
#> <chr> <int> <int>
#> 1 library 1583 1
#> 2 information 583 1
#> 3 data 437 1
#> 4 librarians 398 1
#> 5 academic 351 2
#> 6 design 338 1
#> 7 analysis 301 1
#> 8 development 254 2
#> 9 collection 283 2
#> 10 research 589 1
#> # … with 193 more rows
If you only wants the top keywords to be displayed,
keyword_table
provides another relatively formal table:
grouped_keywords %>%
keyword_table()
#> # A tibble: 2 × 2
#> Group `Keywords (TOP 10)`
#> <int> <chr>
#> 1 1 library (1583); research (589); information (583); data (437); universi…
#> 2 2 academic (351); collection (283); development (254); academic libraries…
In such implementation, only two groups are found. You can specify the number of top keywords using “top” parameter.
Currently, keyword_vis
,keyword_network
and
keyword_cloud
could all be used to draw plots for the
network, but in differnt forms. Let’s try to draw a word cloud
first:
grouped_keywords %>%
keyword_cloud()
To get the word cloud of one group,use:
grouped_keywords %>%
keyword_cloud(group_no = 1)
If you want to draw a network, use keyword_network
:
grouped_keywords %>%
keyword_network()
#> Joining, by = c("name", "freq", "group")
In the plot, “N=106” means altogether there are 106 keywords in the group, though only the top 10 by frequency are showed in the graph. If you only want to visualize the second group and display 20 nodes, try:
grouped_keywords %>%
keyword_network(group_no = 2,max_nodes = 20)
Have fun playing with akc!